Question bank/JEE Advanced/Physics

JEE AdvancedPhysicsChallengingJEE Adv 2017 Paper 2

A photoelectric material having work-function ϕ0\phi_{0} is illuminated with light of wavelength λ(λ<hcϕ0)\lambda\left(\lambda<\frac{h c}{\phi_{0}}\right). The fastest photoelectron has a de Broglie wavelength λd\lambda_{d}. A change in wavelength of the incident light by Δλ\Delta \lambda results in a change Δλd\Delta \lambda_{d} in λd\lambda_{d}. Then the ratio Δλd/Δλ\Delta \lambda_{d} / \Delta \lambda is proportional to

[A]λd/λ[\mathrm{A}] \quad \lambda_{d} / \lambda

[B]λd2/λ2[\mathrm{B}] \quad \lambda_{d}^{2} / \lambda^{2}

[C]λd3/λ[\mathrm{C}] \lambda_{d}^{3} / \lambda

[D]λd3/λ2[\mathrm{D}] \lambda_{d}^{3} / \lambda^{2}

Show answer and solution
Verified official answer key: (D).

Source: JEEBench (IIT Delhi) / JEE Adv 2017 Paper 2

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.