Question bank/JEE Advanced/Physics

JEE AdvancedPhysicsChallengingJEE Adv 2018 Paper 2

A solid horizontal surface is covered with a thin layer of oil. A rectangular block of mass m=0.4 kgm=0.4 \mathrm{~kg} is at rest on this surface. An impulse of 1.0 N1.0 \mathrm{~N} is applied to the block at time t=0t=0 so that it starts moving along the xx-axis with a velocity v(t)=v0e−t/τv(t)=v_{0} e^{-t / \tau}, where v0v_{0} is a constant and τ=4 s\tau=4 \mathrm{~s}. What is the displacement of the block, in metres, at t=τt=\tau? Take e−1=0.37e^{-1}=0.37

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Verified official answer key: (6.3).

Source: JEEBench (IIT Delhi) / JEE Adv 2018 Paper 2

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