Question bank/JEE Advanced/Chemistry

JEE AdvancedChemistryChallengingJEE Adv 2020 Paper 1

Consider a 70\% efficient hydrogen-oxygen fuel cell working under standard conditions at 1 bar and 298 K298 \mathrm{~K}. Its cell reaction is

H2(g)+12O2(g)→H2O(l)\mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{O}(l)

The work derived from the cell on the consumption of
1.0×10−3 molof2(g)1.0 \times 10^{-3} \mathrm{~mol} \mathrm{of}_{2}(g) is used to compress 1.00 mol1.00 \mathrm{~mol} of a monoatomic ideal gas in a thermally insulated container. What is the change in the temperature (in K) of the ideal gas?

The standard reduction potentials for the two half-cells are given below.


O2(g)+4H+(aq)+4e−→2H2O(l),E0=1.23 V,2H+(aq)+2e−→H2(g),E0=0.00 V\begin{gathered} \mathrm{O}_{2}(g)+4 \mathrm{H}^{+}(a q)+4 e^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(l), \quad E^{0}=1.23 \mathrm{~V}, \\ 2 \mathrm{H}^{+}(a q)+2 e^{-} \rightarrow \mathrm{H}_{2}(g), \quad E^{0}=0.00 \mathrm{~V} \end{gathered}

Use
F=96500Cmol−1,R=8.314 J mol−1 K−1F=96500 \mathrm{C} \mathrm{mol}^{-1}, R=8.314 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}.

Show answer and solution
Verified official answer key: (13.32).

Source: JEEBench (IIT Delhi) / JEE Adv 2020 Paper 1

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