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JEE AdvancedMathematicsChallengingJEE Adv 2020 Paper 2

Let OO be the centre of the circle x2+y2=r2x^{2}+y^{2}=r^{2}, where r>52r>\frac{\sqrt{5}}{2}. Suppose PQP Q is a chord of this circle and the equation of the line passing through PP and QQ is 2x+4y=52 x+4 y=5. If the centre of the circumcircle of the triangle OPQO P Q lies on the line x+2y=4x+2 y=4, then what is the value of rr?

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Verified official answer key: (2).

Source: JEEBench (IIT Delhi) / JEE Adv 2020 Paper 2

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