Question bank/JEE Advanced/Mathematics

JEE AdvancedMathematicsChallengingJEE Adv 2021 Paper 1

Three numbers are chosen at random, one after another with replacement, from the set S={1,2,3,…,100}S=\{1,2,3, \ldots, 100\}. Let p1p_1 be the probability that the maximum of chosen numbers is at least 81 and p2p_2 be the probability that the minimum of chosen numbers is at most 40 . What is the value of 1254p2\frac{125}{4} p_{2}?

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Verified official answer key: (24.5).

Source: JEEBench (IIT Delhi) / JEE Adv 2021 Paper 1

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