Question bank/JEE Advanced/Mathematics

JEE AdvancedMathematicsChallengingJEE Adv 2021 Paper 2

Let f1:(0,∞)→Rf_1:(0, \infty) \rightarrow \mathbb{R} and f2:(0,∞)→Rf_2:(0, \infty) \rightarrow \mathbb{R} be defined by
f1(x)=∫0x∏j=121(t−j)jdt,x>0f_1(x)=\int_0^x \prod_{j=1}^{21}(t-j)^j d t, x>0
and

f2(x)=98(x−1)50−600(x−1)49+2450,x>0f_2(x)=98(x-1)^{50}-600(x-1)^{49}+2450, x>0
where, for any positive integer
n\mathrm{n} and real numbers a1,a2,…,an,∏i=1nai\mathrm{a}_1, \mathrm{a}_2, \ldots, \mathrm{a}_{\mathrm{n}}, \prod_{i=1}^{\mathrm{n}} \mathrm{a}_i denotes the product of a1,a2,…,an\mathrm{a}_1, \mathrm{a}_2, \ldots, \mathrm{a}_{\mathrm{n}}. Let mi\mathrm{m}_i and ni\mathrm{n}_i, respectively, denote the number of points of local minima and the number of points of local maxima of function fi,i=1,2f_i, i=1,2, in the interval (0,∞)(0, \infty). What is the value of 6m2+4n2+8m2n26 m_{2}+4 n_{2}+8 m_{2} n_{2}?

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Verified official answer key: (6).

Source: JEEBench (IIT Delhi) / JEE Adv 2021 Paper 2

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