Question bank/JEE Advanced/Mathematics

JEE AdvancedMathematicsChallengingJEE Adv 2020 Paper 2

Let the function f:[0,1]→Rf:[0,1] \rightarrow \mathbb{R} be defined by

f(x)=4x4x+2f(x)=\frac{4^{x}}{4^{x}+2}

Then what is the value of

f(140)+f(240)+f(340)+⋯+f(3940)−f(12)f\left(\frac{1}{40}\right)+f\left(\frac{2}{40}\right)+f\left(\frac{3}{40}\right)+\cdots+f\left(\frac{39}{40}\right)-f\left(\frac{1}{2}\right)?

Show answer and solution
Verified official answer key: (19).

Source: JEEBench (IIT Delhi) / JEE Adv 2020 Paper 2

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.