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JEE MainChemistryToughInorganic Chemistry
A- (g) [IMAGE] A^2+ (g) [IMAGE] H
= 1100 KJ/mol
A (g) [IMAGE] A^2+ (g) [IMAGE] H = 1200
Electron gain enthalpy of A is P × 10^2 KJ/mol. What is the value of P
?
Show answer and solution
1
A (g) [IMAGE] A- (g)
1200-1100 = 100 KJ/mol
A (g) [IMAGE] A- (g)
1200-1100 = 100 KJ/mol
Source: Grass-G / CH-05 Chemistry Paper 10 October.docx
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