Question bank/JEE Main/Chemistry

BaCl_2 + Na_3PO_4[IMAGE] Ba_3(PO_4)_2 + NaCl
Which of the following statement (s) are correct, when 2 mol each of
Na_3PO_4 and BaCl_2 reacts ?
(I) 6 mol NaCl is formed.
(II) 2/3 mol of Ba3(PO_4)_2 is formed.
(III) Na_3PO_4 is Limiting reagent
(IV) 2/3 mol of Na_3PO_4 is left.
(V) BaCl_2 is Limiting reagent.

AI and VBII and IIICII, III and IVDII, IV and V
BaCl_2 + Na_3PO_4[IMAGE] Ba_3(PO_4)_2 + NaCl

Show answer and solution▾

3BaCl_2 + 2Na_3PO_4[IMAGE] Ba_3(PO_4)_2 +
6NaCl
$\because$ 3 mol of Basl_2 reacts with 2 mol Na_3PO_4
$\therefore$ 2 mol of BaCl_2 reacts with
$= \frac{2}{3} \times 2 = \frac{4}{3}$ mol Na_3 PO_4
Reacted mol of Na_3PO_4$= \frac{4}{3}$ mol

Source: Grass-G / CH-05 Chemistry Paper 10 October.docx