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JEE MainChemistryEasyPhysical Chemistry

The energy required to melt 1g ice is 33J. The number of quanta
of radiation of frequency 4.67 ×10^13 sec^-1, that must be absorbed
to melt 10 g ice is

Show answer and solution
ΔE = n.h.(ν) 
33 x 10 J= n. 6.62×10−34 J⋅s 6.62 \times 10⁻³⁴\ J \cdot s\ `<!- ->`4.67
×10^13 sec^-1
n = 1.065 ×10^22

Source: Grass-G / CH-06 Chemistry Paper 14 October.docx

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