Question bank/JEE Main/Chemistry

JEE MainChemistryModeratePhysical Chemistry

Given that in H-atom, the transition energy for n = 1 to n = 2
is 10.2 eV, the energy for the same transition in Be^3+ is

Show answer and solution
Δ\DeltaE = z^2 x 10.2 ev
=16 x 10.2 ev
=162.3 ev

Source: Grass-G / CH-06 Chemistry Paper 14 October.docx

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