Question bank/JEE Main/Chemistry

JEE MainChemistryEasyPhysical Chemistry

The work done in ergs for the reversible expansion of one mole
of an ideal gas from a volume of 10 litres to 20 litres at 25ºC is

Show answer and solution
W=2.303V2V1 W = 2.303\frac{V_{2}}{V_{1}}\
=2.303×1×8.314×107×298log⁡log⁡ 2010 = 2.303 \times 1 \times 8.314 \times 10^{7} \times 298\log\log\ \frac{20}{10}\
=298×107×8.314×2.303log2= 298 \times 10^{7} \times 8.314 \times 2.303log2.

Source: Grass-G / CH-11 Chemistry Paper-2 1Nov New Jee main.docx

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