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JEE MainChemistryModeratePhysical Chemistry

In the combustion of 2.0 gm of methane 25 kcal heat is
liberated; heat of combustion of methane would be
____________________ kcal

Show answer and solution
CH4+2O2→CO2+2H2O{CH}_{4} + 2O_{2} \rightarrow {CO}_{2} + 2H_{2}O
 \ Molecular weight of CH_4 = 12 + 4 = 16
∴\therefore On the combustion of 2.0 gm of methane = 25.0 kcal
On the combustion of 16.0gm =25×162= \frac{25 \times 16}{2} = 200 kcal.

Source: Grass-G / CH-11 Chemistry Paper-2 1Nov New Jee main.docx

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