Question bank/JEE Main/Chemistry

The vapour pressure lowering caused by the addition of 100 g of
sucrose (molecular mass = 342 to 1000 g of water if the vapour
pressure of pure water at 25ºC is 23.8 mm Hg.

A1.25 mm HgB0.125 mm HgC1.15 mm HgD00.12 mm Hg

Show answer and solution▾

Given molecular mass of sucrose = 342
Moles of sucrose [IMAGE] = 0.292 mole
Moles of water N [IMAGE] = 55.5 moles and vapour pressure
of pure water P^0 = 23.8 mm Hg
According to Raoult's law
[IMAGE] = 0.125 mm Hg.

Source: Grass-G / CH-13 Chemistry Paper 4 Nov..docx