Question bank/JEE Main/Chemistry

For the coagulation of 200 mL of As2S3 solution, 10 mL of 1 M
NaCl is required. What is the coagulating value (number of milli moles
of solute needed for coagulation of 1 liter of solution) of NaCl.

A200B100C50D25

Show answer and solution▾

10 ml of 1 M NaCl contains NaCl = 10 × 1 = 10 milli mole
200 ml of As2S3 required NaCl for the coagulation = 10 milli mole
[IMAGE] 1000 ml of As2S3 required NaCl for the
coagulation = 10 × 1000/200 = 50 milli mole

Source: Grass-G / CH-15 Chemistry Paper 11 Nov..docx