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JEE MainChemistryModerateEquivalent Concept

In the ionic equation
2K+BrO3−+12H++10e−⟶Br2+6H2O+2K+2K^{+}B{rO}_{3}^{-} + 12H^{+} + 10e^{-} \longrightarrow {Br}_{2} + 6H_{2}O + 2K^{+},
the equivalent weight of KBrO3 will be

Show answer and solution
BrO2⟶Br2{BrO}_{2} \longrightarrow {Br}_{2}
+5 0

∴(V.f.)BrO3−=5\therefore(V.f.){BrO}_{3}^{-} = 5

Source: Grass-G / CH-16 Chemistry Paper 25 Nov. Fisrt.docx

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