Question bank/JEE Main/Chemistry

JEE MainChemistryEasyIdeal Gas

Pressure of the gas in column

Show answer and solution
Pg=1=75−1012−20×6.813.6×12=60cm of HgP_{g = 1} = 75 - \frac{101}{2} - \frac{20 \times 6.8}{13.6} \times \frac{1}{2} = 60cm\ of\ Hg

Source: Grass-G / CH-18 Chemistry Paper 27 Nov. Third.docx

More JEE Main questionsChapter practice

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.

Scan a doubtView plans