Question bank/JEE Main/Chemistry
JEE MainChemistryToughIdeal Gas
When 100 ml of a O2 - O3 mixture was passed through turpentine,
there was reduction of volume by 20 ml. If 100 ml of such a mixture is
heated, what will be the increase in volume? [Hint: O3 is absorbed by
Show answer and solution
In the mix., volume of O3 = 20 ml, Volume of O2 = 80 ml
on heating 2O3 → 3O2
20 ml O3 will give × 20 = 30 ml O2
total volume = 80 + 30 = 110 ml
increase in volume = 110 - 100 = 10 ml.
on heating 2O3 → 3O2
20 ml O3 will give × 20 = 30 ml O2
total volume = 80 + 30 = 110 ml
increase in volume = 110 - 100 = 10 ml.
Source: Grass-G / CH-18 Chemistry Paper 27 Nov. Third.docx
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