Question bank/JEE Main/Chemistry

JEE MainChemistryModerateEquivalent Concept

25 mL of a solution of Fe2+ ions was titrated with a solution of
the oxidizing agent Cr2O72-. 50 mL of 0.01 M K2Cr2O7 solution was

required. What is the molarity of the Fe2+ solution?

Show answer and solution
[IMAGE] No. of m.eq. of Fe+2 = No. of m.eq. of Cr2O7-2
[M×25]×1=[0.01×50]×6\lbrack M \times 25\rbrack \times 1 = \lbrack 0.01 \times 50\rbrack \times 6
M=0.01×50×625M = \frac{0.01 \times 50 \times 6}{25}
M=0.02×6=0.12M = 0.02 \times 6 = 0.12

Source: Grass-G / CH-18 Chemistry Paper 27 Nov. Third.docx

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