Question bank/JEE Main/Chemistry

JEE MainChemistryEasyOrganic Chemistry

Identify the product D in the following series of reaction
CH3COOH⟶LLiHAAH+443K→B⟶Br2Caic.KOH→D{CH}_{3}COOH\overset{LLiHA}{\longrightarrow}A\frac{H^{+}}{443K} \rightarrow B\overset{{Br}_{2}}{\longrightarrow}C\frac{aic.}{KOH} \rightarrow D

Show answer and solution
CH3−COOH→LiAlH4CH3−CH2−OHH+443K→{CH}_{3} - COOH\overset{{LiAlH}_{4}}{\rightarrow}{CH}_{3} - {CH}_{2} - OH\frac{H^{+}}{443K} \rightarrow
CH2=CH2⟶Br2CH2−CH2alc.KOH{CH}_{2} = {CH}_{2}\overset{{Br}_{2}}{\longrightarrow}{CH}_{2} - {CH}_{2}\frac{alc.}{KOH}
| |
Br Br
CH≡CH+2KBr+2H2OAcetylene\begin{matrix} & CH \equiv CH + 2KBr + 2H_{2}O \\ & Acetylene \end{matrix}

Source: Grass-G / CH-20 Chemistry Paper 12 Dec..docx

More JEE Main questionsChapter practice

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.

Scan a doubtView plans