JEE MainChemistryModeratePhysical Chemistry

Extraction of copper by smelting uses silica as an additive tore
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The reaction involved in the smelting process is given by,

Q = \frac{\pi r^{4}}{8\eta}\frac{\Delta P}{L}

\frac{P_{1}r_{1}^{4}}{l_{1}} = \frac{P_{2}r_{2}^{4}}{l_{2}}

In this prosses

\frac{P_{r_{1}}^{4}}{l_{1}} = \frac{4P_{1}r_{2}^{4}}{\frac{I_{1}}{4}}

forms the flux and

u_{initial\ } = \frac{5}{2}

NRT

r_{2}^{4} = \frac{r_{1}^{4}}{16}

r_{2} = \frac{r_{1}}{2}

forms the gangue which results in the formation of

u_{final\ } = \frac{3}{2}(2nRT) + \frac{5}{2}(N - n)RT

= \frac{1}{2}nRT + \frac{5}{2}NRT

Source: Grass-G / CH-22 Chemistry Paper 19 Dec. Eng.docx

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