JEE MainChemistryEasyPhysical Chemistry

Excess of silver nitrate is added to a water sample to determine
the amount of chloride ion present in the sample. 1.4 g of silver
chloride is precipitated. The mass of chloride ion present in the sample
is:
Molar masses (g-mol-1): AgNO3 169.91, AgCl 143.25

Show answer and solution

{AgNO}_{3} + {Cl}^{-} \longrightarrow AgCl \downarrow + {NO}_{3}^{-}

1.4 g

= \frac{1.4}{143.5}mol

= \frac{1.4}{143.25} \times 35.5gmCl = 0.35gm

Source: Grass-G / CH-23 Chemistry Paper 31 Dec. FST.docx

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