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JEE MainChemistryEasyPhysical Chemistry

[IMAGE] of N_2H_4 is 4 × 10^-6. Then, what is
the acid dissociation constant of [IMAGE] and
[IMAGE] respectively ?


Show answer and solution
Ka1=KwKb1=10−144×10−6=2.5×10−9K_{a_{1}} = \frac{K_{w}}{K_{b_{1}}} = \frac{10^{- 14}}{4 \times 10^{- 6}} = 2.5 \times 10^{- 9}
Kb2 K_{b_{2}}\ data not given, so Ka2\ K_{a_{2}} cannot be determined.

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx

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