JEE MainChemistryModeratePhysical Chemistry

In above question, concentration of Triethyl ammonium ion
([C_6NH_16^+]) in resulting solution will be

Show answer and solution

K_{b} = \frac{\left\lbrack {OH}^{-} \right\rbrack\left\lbrack C_{6}{NH}_{16}^{+} \right\rbrack}{\left\lbrack C_{6}{NH}_{15} \right\rbrack} \Rightarrow \frac{\frac{10^{- 2}}{2}\left\lbrack C_{\theta}{NH}_{16}^{+} \right\rbrack}{\frac{10^{- 2}}{2}} \Rightarrow \left\lbrack C_{6}{NH}_{16}^{+} \right\rbrack = K_{b}

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx

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