JEE MainChemistryEasyPhysical Chemistry

Consider an aqueous solution, 0.1 M each in HOCN, HCOOH,
(COOH)_2 and H_3PO_4. For HOCN, we can write: K_a (HOCN) =
$\frac{\left\lbrack H^{+}I{OCN}^{-} \right\rbrack}{\lbrack HOCN\rbrack}$ . in this equation is

Show answer and solution

For HOCN^-, K_a =

\frac{\left\lbrack H^{+} \right\rbrack\left\lbrack {OCN}^{-} \right\rbrack}{\lbrack HOCN}

= total H^+ concentration of solution.

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx

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