JEE MainChemistryModeratePhysical Chemistry

The figure show the change in concentration of species A and B as
a functional of time. The equilibrium constant K_C for the reaction
$A(g) \rightleftharpoons 2B(g)$ is

Show answer and solution

K_{c} = \frac{\lbrack B\rbrack^{2}}{\lbrack A\rbrack} = \frac{(0.4)^{2}}{0.1} = 1.6

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx

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