If the equilibrium constant of the reaction is 0.25, find the equilibrium constant of the reaction.

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If the equilibrium constant of the reaction
$2HI(g) \rightleftharpoons H_{2}(g) + I_{2}(g)$ is 0.25, find the
equilibrium constant of the reaction.
$\frac{1}{2}H_{2} + \frac{1}{2}I_{2} \rightleftharpoons HI(g)$

Show answer and solution

H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g)

K^{'} = \frac{1}{0.25} = 4

For reaction

\frac{1}{2}H_{2} + \frac{1}{2}I_{2} \rightleftharpoons HI(g)

K^{''} = \sqrt{4}

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx

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