JEE MainChemistryModeratePhysical Chemistry

For a solution of weak triprotic acid H_3A
[IMAGE],[A^3-] = 10^-17 M. Determine pH of
solution. Report your answer as if you find data insufficient.

Show answer and solution

{HA}^{2 -}\ \ \ \ \ \ \rightleftharpoons \ \ \ \ \ \ \ \ \ \ \ \ H^{+} + \ \ \ \ \ \ \ \ \ A^{3 -}

; K_a3 = 10^-13
t = eq; 10^-8 10^-17

\frac{\left\lbrack H^{+} \right\rbrack \times 10^{- 17}}{10^{- 8}} = 10^{- 13}

So, = 10^-4 M

\therefore

pH = 4

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx

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