Question bank/JEE Main/Chemistry
JEE MainChemistryModeratePhysical Chemistry
The value of Kp for the reaction,
is
0.03 atm at 427º C, when the partial pressure are expressed in
atmosphere then the value of KC for the same reaction is
Show answer and solution
Kp = 0.03 T = 427oC = 700 K
Kp = KC(RT)1
KC = 5.23 × 10-4
Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx
Need a video for this idea?
Scan any doubt from your notes and get a whiteboard explanation.