Question bank/JEE Main/Chemistry

Equilibrium constant for the reactions,
${NO}_{2} + {SO}_{2} \rightleftharpoons {SO}_{3} + NO$ is
$2{SO}_{3} \rightleftharpoons 2{SO}_{2} + O_{2}$ is
[IMAGE] then correct reaction is

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(i) $2NO + O_{2} \rightleftharpoons 2{NO}_{2}$
(ii) ${NO}_{2} + {SO}_{2} \rightleftharpoons {SO}_{3} + NO$
(iii) $2{SO}_{3} \rightleftharpoons 2{SO}_{2} + O_{2}$
Now, - 2 (ii) = (i) + (iii)

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx