Question bank/JEE Main/Chemistry

(a)$\ {CuSO}_{4}.5H2O(s) \rightleftharpoons {CuSO}_{4} \cdot 3H_{2}O(s) + 2H_{2}O(g)$
K_P = 4 × 10^-4 atm^2
(b)$\ {Na}_{2}{SO}_{4} \cdot 10H_{2}O(s) \rightleftharpoons {Na}_{2}{SO}_{4.5}H_{2}O(s) + 5H_{2}O(g)$
K_P = 2.43 × 10^-8 atm^5
(c)
${Na}_{2}S_{2}O_{3} \cdot 5H_{2}O(s) \rightleftharpoons {Na}_{2}S_{2}O_{3} \cdot 2H_{2}O(s) + 3H_{2}O(g)$K_P
= 6.4 × 10^-5 atm^3
What is order of pressure of water vapours at equilibrium and relative
humidity respectively.

Ac > b > a V.P.
c > b > a R.H.Bc < b < a V.P.
c > b > a R.H.Ca > c > b V.P.
a > c > b R.H.Da > c > b V.P.
a < c < b R.H.

Show answer and solution▾

[IMAGE] = 2 × 10^-2
[IMAGE] = 243 × 10-10 = [IMAGE] = 3 × 10^-2
[IMAGE] = 6.4 × 10^-5 = [IMAGE] = 4 × 10^-2
Order of V.P c > b > a
and same as c > b > a

Source: Grass-G / CH-24 Chemistry Paper 31 Dec..docx