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JEE MainChemistryEasyOrganic Chemistry

The number of π\pi-bonds present in pent-1-en-4-yne is:
isUV-1-bZu-4-vkbZu v.kqvksa π\picU/kksa

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Pent-4-ene-1-yne
CH2=CH−CH2−C=CH{CH}_{2} = CH - {CH}_{2} - C = CH
No. of π\pi -bonds: 1(C=C)+2(C≡C)=31(C = C) + 2(C \equiv C) = 3
CH2=CH−CH2−C=CH{CH}_{2} = CH - {CH}_{2} - C = CH
π\pi - la 1(C=C)+2(C≡C)=31(C = C) + 2(C \equiv C) = 3

Source: Grass-G / CH-25 Chemistry Paper 7 Jan.docx

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