Question bank/JEE Main/Chemistry

JEE MainChemistryModerateOrganic Chemistry

One mole of a symmetrical alkene on ozonolysis gives two moles
of an aldehyde having a molecular mass of 44 u. The alkene is n-butene.

Find n.,d lefer,sYdhu ds,d vkst+ksuh vi?kVu djus ij,d,sfYMgkbM ds

nks eksy izkIr gksrs gSa,sYdhu n A n

Show answer and solution
CnH2nO=44C_{n}H_{2n}O = 44
CnH2n=44−16C_{n}H_{2n} = 44 - 16
CnH2n=28C_{n}H_{2n} = 28
n=2n = 2
CH3−CH=CH−CH3→O3/ZnCH3−CH=O{CH}_{3} - CH = CH - {CH}_{3}\overset{O_{3}/Zn}{\rightarrow}{CH}_{3} - CH = O

Source: Grass-G / CH-25 Chemistry Paper 7 Jan.docx

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