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JEE MainChemistryModeratePhysical Chemistry
In the depression of freezing point experiment, it is found that:
I. The vapour pressure of the solution is less than that of pure
solvent.
II. The vapour pressure of the solution is more than that of pure
solvent.
III. Only solute molecules solidify at the freezing point.
IV. Only solvent molecules solidify at the freezing point.
III. dsoy v.kq gh fgekad ij Bksl esa ifjofrZr gksrs gSA
IV. dsoy v.kq gh fgekad ij Bksl
Show answer and solution
The freezing point of a solvent depresses as a non-volatile
solute is added to a solvent. According to Raoult's law, when a
non-volatile solute is added to a solvent the vapour pressure of the
solvent decreases. At freezing point it will be only the solvent
molecules which will solidify.
?kV A vuqlkj tc vok" tks rks ok"i nkc ?kV aA fgekad ij dsoy
foyk;d
solute is added to a solvent. According to Raoult's law, when a
non-volatile solute is added to a solvent the vapour pressure of the
solvent decreases. At freezing point it will be only the solvent
molecules which will solidify.
?kV A vuqlkj tc vok" tks rks ok"i nkc ?kV aA fgekad ij dsoy
foyk;d
Source: Grass-G / CH-26 Chemistry Paper 1 15 Jan.docx
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