JEE MainChemistryModeratePhysical Chemistry

The elevation in boiling point of a solution of 13.44 g of CuCl2
in 1kg of water using the following information, will be (Molecular
weight of CuCl2 = 134.4 and Kb = 0.52 K molal-1):
1kg ty esa 13.44 g CuCl2 DoFkukad fuEu lwpuk djrs gq,] gksxk dk v.kqHkkj (CuCl2 = 134.4 o Kb = 0.52 K
molal-1)

Show answer and solution

\Delta T_{0} = iK_{0}m

i (vant Haff factor) of ¼okUVgkWQ
xq.kkad½ CuCI2 = 3

\Delta T_{b} = 3 \times 0.52 \times \frac{13.44}{134.4 \times 1} = 0.156 = 0.16

Source: Grass-G / CH-26 Chemistry Paper 1 15 Jan.docx

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