Question bank/JEE Main/Chemistry

For the reaction, CO(g) + Cl2 (g) [IMAGE] COCl2
(g) then Kp / Kc is equal to:
CO(g) + Cl2 (g) [IMAGE] COCl2 (g) vfHkfØ fy,] Kp /
Kc fuEu

A1.0B$\sqrt{RT}$CRT

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CO(g) + Cl2 (g) [IMAGE] COCl2 (g)
Δn = 1 - 2 = - 1; K_p = K_c (RT)^Δn $\therefore$
$\frac{K_{p}}{K_{c}} = (RT)^{- 1} = \frac{1}{RT}$

Source: Grass-G / CH-27 Chemistry Paper 2 15 Jan.docx