JEE MainChemistryModeratePhysical Chemistry

For the reaction equilibrium, N2O4 (g)[IMAGE] 2NO2
(g) the concentrations of N2O4 and NO2 at equilibrium are 4.8 × 10-2
and 1.2 × 10-2 mol L-1 respectively. The reaction for Kc =___ ×
10-3

Show answer and solution

= 4.8 × 10-2 mol L-1, = 1.2 × 10-2 mol L-1

K_{c} = \frac{\left. \ {\lbrack NO}_{2} \right\rbrack^{2}}{\left\lbrack N_{2}O_{4} \right\rbrack} = \frac{1.2 \times 10^{- 2} \times 1.2 \times 10^{- 3}}{4.8 \times 10^{- 2}}

= 0.3 × 10-2 = 3 × 10-3 mol L-1

Source: Grass-G / CH-27 Chemistry Paper 2 15 Jan.docx

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