Question bank/JEE Main/Chemistry
JEE MainChemistryModeratePhysical Chemistry
The Henry's law constant for the solubility of N2 gas in water
at 298 K is 1.0 × 105 atm. The mole fraction of N2 in air is 0.8. The
number of moles of N2 from air dissolved in 10 moles of water of 298 K
and 5 atm pressure is:
N2 xSl dh ty esa ? fy, gsujh fu;e fLFkjkad (Henry's law
constant) dk eku 298 K ij 1.0 × 105 atm gSA N2 izHkkt
mifLFkr N2
Show answer and solution
eksy
In 10 mole solubility is eksy
Source: Grass-G / CH-27 Chemistry Paper 2 15 Jan.docx
Need a video for this idea?
Scan any doubt from your notes and get a whiteboard explanation.