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JEE MainChemistryModeratePhysical Chemistry

6.02 × 1020 molecules of urea are present in 100 ml of its
solution. The concentration of urea solution is:
lkUnzrk

Show answer and solution
Moles of urea
=6.02×10206.02×1023=10−3moles= \frac{6.02 \times 10^{20}}{6.02 \times 10^{23}} = 10^{- 3}moles
Concentration (molarity) of solution ¼eksyjrk½
=10−3100×1000=0.01M= \frac{10^{- 3}}{100} \times 1000 = 0.01M

Source: Grass-G / CH-27 Chemistry Paper 2 15 Jan.docx

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