Question bank/JEE Main/Chemistry

JEE MainChemistryModeratePhysical Chemistry

The solubility of Ag2CO3 in water ­­is 1.26 × 10-4 mole/litre.
What is its solubility in 0.02 M Na2CO3 solution ? Assume no hydrolysis

of CO32- ion. (Take = 1.26)

ty esa Ag2CO3 1.26 x 10-4 eksy@yhVj

esa bl ekusa fd CO32- vk;u

Show answer and solution
Na2CO3 [IMAGE] 2Na+ + CO32-
2 × 0.01 0.01

Ag2CO3 [IMAGE] 2 Ag+ + CO32-

2 x (x + 0.01)
≈\approx 0.01
Ksp = 4x2 (0.01)

Ksp = 4s3 = 4 × 10-12 = 4x2 (0.01)
⇒\Rightarrow x = 10-5

Source: Grass-G / CH-27 Chemistry Paper 2 15 Jan.docx

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