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JEE MainChemistryEasy / Moderate/ Tough tPhysical Chemistry

The average velocity of gas molecules is 400 m/sec calculate its
r.m.s. velocity at the same temperature

Show answer and solution
Uav=8RTπMU_{av} = \sqrt{\frac{8RT}{\pi M}} and
Urms=3RTMU_{rms} = \sqrt{\frac{3RT}{M}}
∴UavUrms=8RTπM×M3RT=83π=0.9216\therefore\frac{U_{av}}{U_{rms}} = \sqrt{\frac{8RT}{\pi M}} \times \sqrt{\frac{M}{3RT}} = \sqrt{\frac{8}{3\pi}} = 0.9216
or
Uav=0.9216×UrmsU_{av} = 0.9216 \times U_{rms}
Given
Uav=400m/sU_{av} = 400m/s
Urms=4000.9216=434.02m/sU_{rms} = \frac{400}{0.9216} = 434.02m/s

Source: Grass-G / CH-28 Chemistry Paper FST 16 Jan.docx

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