Question bank/JEE Main/Chemistry

JEE MainChemistryEasy / Moderate/ Tough mPhysical Chemistry

For the reaction:
C2H5OH(l)+3O2(g)⟶2CO2(g)+3H2O(g)C_{2}H_{5}OH(\mathcal{l}) + 3O_{2}(g) \longrightarrow 2{CO}_{2}(g) + 3H_{2}O(g)
if

ΔUo=−1373kJmol−1\Delta U^{o} = - 1373kJ{mol}^{- 1} at 298 K. Calculate ΔHo\ \Delta H^{o}

Show answer and solution
ΔHo=ΔUo+ΔngRT\Delta H^{o} = \Delta U^{o} + \Delta n_{g}RT
=−1373+2×8.314×2981000= - 1373 + 2 \times \frac{8.314 \times 298}{1000}
=−1368 kJ mol−1= - 1368\ kJ{\ mol}^{- 1}

Source: Grass-G / CH-28 Chemistry Paper FST 16 Jan.docx

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