Electron gain enthalphy of A is . What is the value of P ?

JEE MainChemistryModerateInorganic Chemistry

$A^{-}(g) \rightarrow A^{2 +}(g)$ $\Delta H = 1100\ KJ/mol$
$A(g) \rightarrow A^{2 +}(g)$ $\Delta H = 1200\ KJ/mol$
Electron gain enthalphy of A is $P \times 10^{2}KJ/mol$ . What is the
value of P ?

Show answer and solution

A(g) + e^{-} \rightarrow A^{-}(g)

\Delta H = + E \cdot G \cdot E

....(1)

A(g) \rightarrow A^{2 +}(g) + 2e^{-}

\Delta H = 1200\ KJ/mol

....(2)

A^{-}(g) \rightarrow A^{2 +}(g) + 3e^{-}

\Delta H = 1100\ KJ/mol

....(3)
Eq. (3) = (2) - (1)

- E \cdot G \cdot E + 1200 = 1100

- E \cdot G \cdot E = - 100\ KJ/mol

P = 1

Source: Grass-G / CH-28 Chemistry Paper FST 16 Jan.docx

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