JEE MainChemistryEasyPhysical Chemistry

The enthalpies of neutralization of a weak base AOH and a strong
base BOH by HCI are -12250 mol respectively.
When one mole of HCI is added to a solution containing 1 mole of AOH and
1 mole of BOH, the enthalpy change was -12500 cal/ mol. In what ratio
the acid is distributed between AOH and BOH?

Show answer and solution

- 12250x - 13000(1 - x) = - 12500

750x = 500 \Rightarrow x = 2/3

So, required ratio is =

\frac{2}{1}

Source: Grass-G / CH-28 Chemistry Paper FST 16 Jan.docx

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