JEE MainChemistryModeratePhysical Chemistry

The equilibrium constant at 298 K for a reaction
$A + B \rightleftharpoons C + D$ is 100. If the initial concentration of
all the four species were 1 M each, then equilibrium concentration of D
(in mol L-1) will be

Show answer and solution

A\ \ \ \ \ \ \ \ \ + \ \ \ \ \ \ \ \ \ B\ \ \ \ \ \ \ \ \ \rightleftharpoons \ \ \ \ \ \ \ \ \ \ C\ \ \ \ \ \ \ \ \ + \ \ \ \ \ \ \ \ D

t = 0 1 1 1 1

t_{eq}

1 - x\

1 - x

1 + x

1 + x

\Rightarrow \frac{(1 + x)^{2}}{(1 - x)^{2}} = 100 \Rightarrow \frac{1 + x}{1 - x} = 10

\Rightarrow 1 + x = 10 - 10x \Rightarrow 11x = 9

\Rightarrow x = \frac{9}{11}

\Rightarrow \lbrack D\rbrack = 1 + \frac{9}{11} \Rightarrow \lbrack D\rbrack = 1.818

Source: Grass-G / CH-28 Chemistry Paper FST 16 Jan.docx

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