Question bank/JEE Main/Mathematics
JEE MainMathematicsToughBinomial Theorem
[IMAGE] x^10 k, k
(log_102=0.3010)
Show answer and solution
Coefficient of x^10 = ^21C_0 + ^21C_1 +..... + ^21C_10
k = 2^21 - 1^ = 220
no. of digits in k = 7
([IMAGE] log_10k = 20 × 0.3010 = 6.020)
k = 2^21 - 1^ = 220
no. of digits in k = 7
([IMAGE] log_10k = 20 × 0.3010 = 6.020)
Source: Grass-G / M-04 Paper 2 Mathematics 18-8-2020_Final.docx
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