ξ^2 - 3x + 1 = 0 α β 
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α^2 - 3α + 1 = 0 ⇒α^2 + 1 = 3α....(i)
Similarly, ⇒β^2 + 1 = 3β....(ii)

Source: Grass-G / M-04 Paper 2 Mathematics 18-8-2020_Final.docx

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