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JEE MainMathematicsModerateLogarithm and its applications

The expression [IMAGE] where p≥2,p∈N;n∈Np \geq 2,p \in N;n \in N when
simplified is

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log⁡Plog⁡P ….. PPPPP\log_{P}{\log_{P}\sqrt[P]{\sqrt[P]{\sqrt[P]{\ \ldots..\ \sqrt[P]{P}}}}}
Take
 ….. PPPPP=︸((((P)1P)1P)….)1Pn times\sqrt[P]{\sqrt[P]{\sqrt[P]{\ \ldots..\ \sqrt[P]{P}}}} = \underset{n\ times}{\overset{\left( \left( \left( (P)^{\frac{1}{P}} \right)^{\frac{1}{P}} \right)^{\ldots.} \right)^{\frac{1}{P}}}{︸}}
=(P)1Pn= (P)^{\frac{1}{P^{n}}}
Now,
log⁡Plog⁡P(P)1Pn\log_{P}^{\log_{P}^{(P)^{\frac{1}{P^{n}}}}}
=logP1Pnlog⁡P p{{= log}_{P}}^{\frac{1}{P^{n}}^{\log_{P}\ p}}
=log⁡P(1P)n= \log_{P}\left( \frac{1}{P} \right)^{n}
=nlog⁡P(P)−1= n\log_{P}(P)^{- 1}
=−nlog⁡PP= - n\log_{P}P

Source: Grass-G / M-05 Mathematics Paper 10 October.docx

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