Question bank/JEE Main/Mathematics

Number of ways 3 girls and 5 boys can be seated around a
circular table such that no two girls sit together and not more than two
boys sit between two girls

A4! × 3!B5 × 4! × 3!C40 × 4! × 3!D15 × 4! × 3!

Show answer and solution▾

Only 5 cases are there when more than two boys can sit between
two girls provided no two girls sit together.
[IMAGE] $\$Hence required no. of
ways $= (5 - 1)!\left\{ \ ^{5}C_{3}3! - 5.3! \right\}$

Source: Grass-G / M-08 Mathematics Paper 23 October.docx