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JEE MainMathematicsToughContinuity and derivability

denotes greatest integer function then,

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f(x)=1+x[cosx];0<x≤π2f(x) = 1 + x\lbrack cosx\rbrack;0 < x \leq \frac{\pi}{2}
f (x) =1 + 0 = 1

⇒\Rightarrowf (x) is constant in (0,π2]\left( 0,\frac{\pi}{2} \right\rbrack
⇒\Rightarrow f (x) is constant and different
able 
∀x∈(0,π2]\forall x \in \left( 0,\frac{\pi}{2} \right\rbrack

Source: Grass-G / M-09 Mathematics Paper 26 October.docx

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